Question

Consider a compound slab consisting of two different materials having equal thickness and thermal conductivities K and 2K respectively. The equivalent thermal conductivity of the slab is?
How do we know if its connected in series or parallel?

Answer 1

Answer:

K eqv. in a series combination is given by 2K'K"/K'+K".

By putting the values you will get 4K/3.

In case of parallel combination K eqv. is given by (K'+K")/2.

By putting the values you will get K eqv. = 3K/2.

Answer 2

Answer:

remember one thing that compound slab is a physical instrument made of 2 different or same slab in series combination.☺️

Explanation:

that's why Keq. = 2K1K2/k1+K2.

i.e. 2×1×2/2+1 =4K/3