Question

Consider a conductor of resistance 5Ω, through which 31.25 x 1010 electrons are flowing for 5 minutes. Calculate the amount of current flowing through it.​

Answer 1

Explanation:

5mA from B to A.

In the question, it is given that the charge of an electron is e=1.6×10

−19

C.

Therefore, the total charge flowing through the wire in 2 seconds will be given as 6.25×10

16

×1.6×10

−19

C=10×10

−3

C.

The rate of flow of charge is therefore

2 seconds

10×10

−3

C

=5×10

−3

C/s.

one C/s = one amp.

Hence, the current flowing through a conductor is 0.0005A, that is 5mA.