Question

consider a conductor of resistance R,length L, thickness d, and resistivity p.now this conductor is cut into four equal parts.what will be the new resistivity of each of these parts ? why ​

Answer 1

Answer:

new resisitence is 1/4th of the previous one

Explanation:

Let the first resistance be R

hence R=rho (p) ×l/a

here l =length of conductot

a=cross-section area

Now , according to question

new lenght say l'= l/4

cross-section area a'=a (same)

hence new resistance say R'=rho(p)×l'/a

=rho × l/4a

Now , R/R'= rho×l/a/ rho × l/4a = 1/4

hence R/R'=1/4