Question

consider a container kept on a horizontal surface having vertical walls of height 5m. its base is in contact with horizontal surface is in the form of a parallelogram from a randomly selected cartesian system two adjacent sides of its base are given by a= i+2j+3k and b=3i+4j+5k. the volume of the container is

Answer 1

Explanation:

Correct option is

C

only v depends on h

The velocity with which the liquid comes out is v

0

=

2gh

.

Let cross-sectional area of the hole be A. Then the force exerted by the ejecting fluid due to change in momentum on the container is F=ρAv

2

F=ρAv

2

=ma, where m is the mass of the liquid inside the container.

ρAv

2

=ρAh×a

⇒a=2g

Differentiating the above equation, we can have v=2gt where t is the time in which the liquid comes out completely which is dependent on h.