Question

Consider a cuboid whose base is a 3cm × 4cm rectangle. If the volume of the cuboid is 60
cm3

, what is the surface area?

Answer 1

Answer:

94cm² is the total surface area.

Explanation:

Given

• Dimensions of base of the cuboid are 3cm × 4cm.
• The volume of the cuboid is 60cm³

To Find:

• The surface area of the cuboid.

Base of the cuboid = Length × breath = 3cm × 4cm

Volume of a cuboid = Length × breath × height

( Substitute 3cm × 4cm in place of length × width)

⟹ 60cm³ = 3cm × 4cm × height

⟹ 60cm³ = 12cm² × height

⟹ 60cm³/12cm² = height

⟹ 5cm = height

Height of the cuboid is 5 cm

Surface area of a cuboid = 2( lb + bh + hl )

• b = base
• h = height
• l = Length

Surface area of the cuboid :

⟹ 2( 4cm × 3cm + 3cm × 5cm + 5cm × 4cm )

⟹ 2( 12cm² + 15cm² + 20cm² )

⟹ 2{ ( 12 + 15 + 20)cm²}

⟹ 2 ( 47cm² )

⟹ 94cm²

94cm² is the total surface area.

Answer 2

Answer:

Base of the cuboid = Length × breath = 3cm × 4cm

Volume of a cuboid = Length × breath × height

( Substitute 3cm × 4cm in place of length × width)

⟹ 60cm³ = 3cm × 4cm × height

⟹ 60cm³ = 12cm² × height

⟹ 60cm³/12cm² = height

⟹ 5cm = height

Height of the cuboid is 5 cm

Surface area of a cuboid = 2( lb + bh + hl )

b = base

h = height

l = Length

Surface area of the cuboid :

⟹ 2( 4cm × 3cm + 3cm × 5cm + 5cm × 4cm )

⟹ 2( 12cm² + 15cm² + 20cm² )

⟹ 2{ ( 12 + 15 + 20)cm²}

⟹ 2 ( 47cm² )

⟹ 94cm²

94cm² is the total surface area