Question

Consider a disk pack with 16 surfaces, 128 tracks per surface and 256 sectors per track. 512 bytes of data are stored in a bit serial manner in a sector. The capacity of the disk pack and the number of bits required to specify a particular sector in the disk are respectively:

Answer 1

Answer:

16 surfaces equal to  =4 bits,Due to  128 number of  tracks =7 bits, 256 number sectors produce  =8 bits,Size of  sector  512 bytes =9 bits .The capacity of disk required  =24+7+8+9=228=256 MB .To specify a specific  sector, it is not necessary to require sector size, so the number of bits required =4+7+8=19. A bit is a binary digit, the smallest amount of increment of data by a  computer or PC. A bit can keep hold only one of two values as:The electrical values, of off or on, represented by 0 or 1,This is due to the small size of bits, you do not frequently work with information related to one bit at a time. Bits gathered into a group of eight to make a byte. A byte consists of a lot of information to store ASCII of a single character, like "h".