Question

Consider a file of 3MB that needs to be transmitted over a 1Gbps link which has a RTT of 80ms. The effective throughput will be:​

Answer 1

Answer:

1Gbps = 109bps, and 1 bit on a 1-Gbps link is 1 / 109 bps = 10-9s wide. If the speed of propagation is 2.3*108 m/s, then the length of a bit is (2.3*108 m/s) * (10-9 s) = 0.23m 15.

I hope it's help you