Question

Consider a gas of Cs atoms at a number density of 102 atoms/cc. when the typical inter- particle distance is equal to the thermal de Broglie wavelength of the particles, the temperature of the gas is nearest to (Take the mass of a Cs atom to be 22.7x10-26 kg) (a) 1x10-9 K (b)7x10-5 K (c)1x10-²K (d) 2x10- K​
nice 2meet uh;xd​

Answer 1

❥︎ANSWER

GMm=rmv2

=r2(21mv2)

⇒r2GMm=r2K

⇒M=Gm2Kr

⇒dM=Gm2Kdr

⇒4πr2drρ=Gm2Kdr

∴ρ=2πGmr2K

⇒mρ=2πGm2r2K Alternative:

r2GM(r)=rV2

Where M(r)= total mass upto radius(r)

❥︎THANKS

I hope it will help you.

Answer 2

Answer:

r

2

GMm

=

r

mv

2

=

r

2

(

2

1

mv

2

)

⇒

r

2

GMm

=

r

2K

⇒M=

Gm

2Kr

⇒dM=

Gm

2K

dr

⇒4πr

2

drρ=

Gm

2K

dr

∴ρ=

2πGmr

2

K

⇒

m

ρ

=

2πGm

2

r

2

K

Alternative:

r

2

GM(r)

=

r

V

2

Where M(r)= total mass upto radius(r)

⇒K=

2r

GMm

⇒M(r)=

Gm

2Kr

⇒dM(r)=

Gm

2K

dr=ρdV=ρ4πr

2

dr

⇒ρ=

G2πr

2

m

K

⇒

m

ρ

=

2πGm

2

r

2

K

Explanation:

hru xD