Consider a gas with density rho and c¯ root mean square velocity of its molecules contained in a volume. If the system moves as whole with velocity v, then the pressure exerted by the gas isA) 1/3rhoc¯2B) 1/3rho(c¯+v)^2C) 1/3rho(c¯−v)^2D) 1/3rho(c^¯2−v)^2
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Answered by
1
Answer:
Root-mean-square speed is the measure of the speed of particles in a gas which is most convenient for problem solving within the kinetic theory of gases
v_{rms}=\sqrt { \frac { 3RT }{ M } } v
rms
=
M
3RT
\Rightarrow C=\sqrt { \frac { 3RT }{ M } } \\ \Rightarrow C=\sqrt { \frac { 3PV }{ M } } \\ \Rightarrow C=\sqrt { \frac { 3P }{ \rho } } \\ \Rightarrow P=\frac { \rho }{ 3 } { C }^{ 2 }=\frac { 1 }{ 3 } \rho { C }^{ 2 }⇒C=
M
3RT
⇒C=
M
3PV
⇒C=
ρ
3P
⇒P=
3
ρ
C
2
=
3
1
ρC
2
Answered by
2
Answer:
1/3 roh c^-2
Explanation:
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