Physics, asked by phalak1707, 1 year ago

Consider a gas with density rho and c¯ root mean square velocity of its molecules contained in a volume. If the system moves as whole with velocity v, then the pressure exerted by the gas isA) 1/3rhoc¯2B) 1/3rho(c¯+v)^2C) 1/3rho(c¯−v)^2D) 1/3rho(c^¯2−v)^2

Answers

Answered by sharfabihari
1

Answer:

Root-mean-square speed is the measure of the speed of particles in a gas which is most convenient for problem solving within the kinetic theory of gases

v_{rms}=\sqrt { \frac { 3RT }{ M } } v

rms

=

M

3RT

\Rightarrow C=\sqrt { \frac { 3RT }{ M } } \\ \Rightarrow C=\sqrt { \frac { 3PV }{ M } } \\ \Rightarrow C=\sqrt { \frac { 3P }{ \rho } } \\ \Rightarrow P=\frac { \rho }{ 3 } { C }^{ 2 }=\frac { 1 }{ 3 } \rho { C }^{ 2 }⇒C=

M

3RT

⇒C=

M

3PV

⇒C=

ρ

3P

⇒P=

3

ρ

C

2

=

3

1

ρC

2

Answered by puneethpeddeti
2

Answer:

1/3 roh c^-2

Explanation:

Similar questions