Question

Consider a gold nucleus to be a sphere os radius 6.9 fermi in which protons and neutrons are distributed. Find the force of repulsion between the two protons situated at largest separation. Why do these protons do not fly apart under this replusion?

Answer 1

Answer:

ANSWER

According to the question,

maximum separation between protons =2r=2×6.9

=13.8ferni

d=13.8×10−15m

Charge on each proton =1.6×10−19

F=(1.38×1014)29×109×(1.6×10−19)2=1.38×1.38×109−38+289×2.56=12.09×10−1N=1.209N

Explanation:

I hope this will help you.