Physics, asked by khushikesarwani20, 11 months ago

Consider a heavy body whose mass is 3*10²⁴ kg and radius is 3200km.What is the acceleration due to gravity at its surface??( G=6.67*10^-11)

Answers

Answered by yuvraj5931
11
M = 3*10^24 kg
R = 3200km = 32*10^5 m
g = ?
G = 6.67*10^-11

F = GMm/R^2 -----------(1)
also,
F = mg ------------(2)
g is a accelaration due to gravity.
compare eqn (1) &(2)
mg = GMm/R^2
:. g = GM/R^2
:. g = (6.67 * 10^-11 * 3*10^24)/(32*10^5)^2
:. g =19.54 m/s^2
Hope this will help u.....
Answered by sumitsolanky12
5

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