Question

Consider a logical address space of 32 pages of 512 words each ,mapped onto a physical memory of 16 frames
1. How many bits are there in the logical addres?
2. How many bits are there in the physical address?

Answer 1

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Answer 2

Answer:

1. 15 bits are there in the logical address
2. 14 bits are there in the Physical address

Explanation:

Address Translation:

Given: Consider a logical address space of 32 pages of 512 words each ,mapped onto a physical memory of 16 frames

To find: Bits are there in the logical address and physical address?

Solution:

• Logical address is generated fig the CPU, this address is also called as virtual address.
• Main memory address uses physical address and this address is called as read address.
• Set of all logical address generated by a program is called as logical address space.
• Memory management unit (MMU) is responsible for routine address mapping from virtual to physical address.

we know that Number of pages = virtual memory space / page size.

and Number of frames = physical memory space / frame size.

and page size is equal to frame size.

According to question and given data:

     virtual memory space = Number of pages * page size

i.e.  virtual memory space = 64 * 512 B

     virtual memory space = 26 * 29B

                 i.e.     = 215B.

So, 15 bits are required for virtual memory space.

physical memory space =  Number of frames * frame size.

physical memory space = 32 * 512 B

physical memory space = 25 * 29B

               i.e.   = 214B.

So, 14 bits are required for virtual memory space