Physics, asked by devansh1396, 3 months ago

Consider a mass -spring system. This system is given an initial displacement it begin to oscillate with frequency f, System is
now bring to rest and again it is given different displacement and f, be its frequency of oscillation then frequencies
O a:f1 =f2
O b.f1 > f2
O c. f1 <f2
O d. none of the above​

Answers

Answered by aryansuts01
0

Answer:

Concept:

The quantity of oscillations a particle performs in a second is referred to as its frequency of oscillation. The particle completes one oscillation in T seconds. Hertz or cycles per second are used to express the oscillation frequency. The number of complete oscillations during a certain period of time, such as a second, is how frequently an oscillation occurs. A pendulum that completes an oscillation in 0.5 seconds has a frequency of 2 oscillations per second, or 1 oscillation every 0.5 seconds.

Given:

Think about a mass-spring setup. This system is initially moved and oscillates at frequency f. It is then brought to rest and given a new displacement, with frequency f acting as the oscillation frequency.

[a]. f1 = f2

[b]. f1 > f2

[c]. f1 < f2

[d]. none of the above​

Find:

find the right response to the provided question's inquiry.

Answer:

The answer is option [b]. f1 > f2

Simply said, a spring-mass system is a spring system with a block hung or fastened to the free end of the spring. The period of any item moving in a simple harmonic motion may typically be determined using the spring-mass system. There are numerous other applications for the spring-mass system. For instance, the spring-mass system can be used to replicate foot skin deformation and the action of human tendons utilizing computer images.

In a closed environment, a spring with mass m and spring constant k exhibits a straightforward harmonic motion.

T = 2π √m/k

It is obvious from the aforementioned equation that neither gravitational acceleration nor amplitude affect the oscillation's period. Furthermore, the period of oscillation cannot be changed by a constant force. While this is happening, the length of time directly relates to the mass of the body that is attached to the spring. If you attach a hefty object to it, it will oscillate more slowly.

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Answered by pankajpal6971
0

Answer:

The correct option is [b]. f1 > f2.

Explanation:

  • A spring system with a block suspended from or fastened to the free end of the spring is known as a spring-mass system.
  • The spring-mass system is generally used to calculate the period of any object in a simple harmonic motion. The spring-mass system has a wide range of additional uses.
  • For example, the spring-mass system can be used to simulate human tendon activity and foot skin deformation using computer images.
  • A spring with mass m and spring constant k displays a simple harmonic motion in a confined environment.

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