Consider a Millikan's oil drop experiment where the two parallel plates are about 30mm apart and are connected to a 800V DC power supply .The electric field just supports an oil drop of mass 2x10^-15 kg. Calculate the charge on the drop of oil .Hence estimate the number of excess electrons acquired by the drop of oil
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answer:
mass= 2×10^-15 kg
Energy=8000v
distance=30 mm
can be solved by formula e=mg /q
then electrons no. we can find
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