Question

Consider a number with 4 different digits. The ones and tens place digits are divisible by 2. Hundreds and thousands place are divisible by 5. How many such numbers all possible? 2

Answer 1

Answer:

If a 4-digit number is formed by using the digits 1,2,3,4,5 (repitition is allowed )

Thousands, Hundreds and Tens place can be filled up with 5 ways each.

So, a total of 5×5×5 ways to fill these three place.

Now, if the given numbers 1,2,3,4,5 are filled in the unit place, they will form 5 consecutive numbers, out of which only one is divisible by 6.

So, total 4-digit numbers divisible by 6 are 5×5×5×1=125

Explanation:

I hope my answer is correct

Answer 2

Answer:

The four digits is =6025

60divide by 2 = 30

25 divide by 5 = 5

305