Consider a number with unit digit 5, i.e., a5
(a5)2 = (10a + 5)
= 10a(10a + 5) + 5(10a + 5)
= 100a+ 50a + 50a + 25
= 100a(a + 1) + 25
= a(a + 1) hundred + 25.
*Please explain it*
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Answered by
4
Answer:
I think that u have solve the answer
Answered by
0
Answer:
a5)2 = (10a + 5)
= 10a(10a + 5) + 5(10a + 5)
= 100a+ 50a + 50a + 25 n explaination [100a +100a]take this as common
[100a sq]
== 100a(a + 1) + 25
= a(a + 1) hundred + 25
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