Question

consider a particl moving along x axis with velocity v= 3tsquare+2t+1 m/s. its acceleration in t=2sec is?

Answer 1

Answer:

At t=0, the particle is at a position 5 m, and at t=4 s the particle is at position 1 m.

Thus displacement of particle  S=1−5=−4 m

Time taken  t=4 s

Average velocity  V  

avg

​  

=  

t

S

​  

=  

4

−4

​  

=−1 m/s

Slope of displacement-time graph gives the velocity of particle at that instant.

Slope of the graph is zero at t=4 s, thus velocity is zero at t=4 s.

Answer 2

it is based on velocity..stay safe