consider a particle intially moving with velocity 5m/s. it starts decelerating at a cobstant of 2m/s^2. calculate the distance travelled in 3 rd second?
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u= 5m, a=-2m/s² ,t=3 sec.,s=?
use 2nd equation of the motion
s=ut+1/2at²
s=5×3+1/2×-3×9
s=15-27/2
s=3/2
s=1.5m
use 2nd equation of the motion
s=ut+1/2at²
s=5×3+1/2×-3×9
s=15-27/2
s=3/2
s=1.5m
Prathmesh9304:
ans is 6 m
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