Question

Consider a particle with mass m=2Kg and position vector
r=2i+j-k m,with respect to the fixed axis of rotation, moves with
linear velocity v=i+j+k m/s. Calculate the angular momentum of the
particle.

Answer 1

Answer:

Position vector

r

=

i

^

+

j

^

Velocity

v

=2

i

^

+3

j

^

m/s

Mass m=2 kg

Angular momentum

L

=m(

r

×

v

)

⟹

L

=2[(

i

^

+

j

^

)×(2

i

^

+3

j

^

)]=2

k

^