Question

Consider a population in which frequency if allele A is 0.6 an frequency of allele a is is 0.4 where allele are co dominant what will be the the frequency

Answer 1

Explanation:

In a stable population, for a gene with two alleles, 'A' (dominant) and 'a' (recessive), if the frequency of 'A' is p and the frequency of 'a' is q, then the frequencies of the three possible genotypes (AA, Aa and aa) can be expressed by the Hardy-Weinberg equation:

p^2+2pq+q^2=1

where p^2 = Frequency of AA (homozygous dominant) individuals

q^2 = Frequency of aa (homozygous recessive) individuals

2pq = Frequency of Aa (heterozygous) individuals.

So, p= 0.6 and q = 0.4 (given)

.'. 2pq (frequency of heterozygote) =2 x 0.6 x 0.4=0.48

So, the answer is '0.48'.