Physics, asked by roses5204, 11 months ago

Consider a radioactive nucleus A which decays to a stable nucleus C through the following sequence A to B to C Here B is an intermediate nuclei which is also radioactive. Considering that there are N_(0) atoms of A initially , plot the praph showing the variation of number of atoms of A and B versus time.

Answers

Answered by Anonymous
2

Answer:

At t = 0, NA = NO while NB = 0. As time increases, NA falls off exponentially, the number of atoms of B increases, becomes maximum and finally decays to zero at ∞ (following exponential decay law).

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Answered by Theopekaaleader
0

Solve the following by both substitution and elimination methods.

2x - \sqrt{2} y = 0

and

 \frac{3x}{ \sqrt{2} } - y = 1

Solve the following by both substitution and elimination methods.

2x - \sqrt{2} y = 0

and

 \frac{3x}{ \sqrt{2} } - y = 1

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