Question

Consider a raster system with resolution of 1280 by 1024. What size of
needed for given system to store 24 bits per pixel ?​

Answer 1

Because eight bits constitute a byte, frame-buffer sizes of the systems are as follows:

640 x 480 x 12 bits / 8 = 450KB; 1280 x 1024 x 12 bits / 8 = 1920KB; 2560 x 2048 x 12 bits / 8 = 7680KB;

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