Physics, asked by anilvnaik8480, 9 months ago

Consider a ray of light incident from air onto a slab of glass
(refractive index n) of width d, at an angle q. The phase
difference between the ray reflected bv the top surface of
the glass and the bottom surface is
(a) 2πd/????(1-1/n² sin²ϴ)¹/² + π
(b) 4πd/????(1-1/n² sin²ϴ)²
(c) 4πd/????(1-1/n² sin²ϴ)¹/² + π/2
(d) 4πd/????(1-1/n² sin²ϴ)¹/² + 2π

Answers

Answered by yogeshparashar452
1

Answer:

4πd/????(1-1/n² sin²ϴ)¹/² + 2π is the answer

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