Consider a rectangular garden in front of a
house, whose dimensions are ( ) 2 6 k + metre
and k metre. A smaller rectangular portion of
the garden of dimensions k metre and 3 metres
is leveled. Find the area of the garden, not
leveled. (2k+6) m k metre k metre 3 metres
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Answer:
... is 1/3 × 12 = 4 ft. The diagonal of this 4-ft-by-12-ft garden is the hypotenuse of a right triangle with legs of length ... Substituting this into the second equation, we get k + 3 = 3(2k – 6 – 3), which becomes k + 3 = 6k ...
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