Question

Consider a relation in aset of all real numbers
R= {(x,y) : x=y, (viniculam) x and y belongs to R }​

Answer 1

S is an equivalence relation but R is not an equivalence relation.

xRy need not implies yRx.

S:s⇔qm=pn

n

m

s

n

m

reflexive.

n

m

s

q

p

=

q

p

s

n

m

symmetric.

n

m

s

q

p

,

q

p

s

s

r

=qm=pn,ps=rqS is an equivalence relation.

=ms=rn transitive.

Answer 2

Step-by-step explanation:

S is an equivalent relation

hope it helps you