Question

Consider a right angle triangle PQR right-angled
at Q. If PQ is 27 cm and QR is 27✓3 cm,
then the angle P is

Answer 1

Answer:

PQR is a triangle right angled at P. If PQ=10cmandPR=24cm, find QR  1:27 · In ΔPQR ∠R=∠P and QR=4cm and PR=5cm Then the length of PQ is 3:26 · A circle is inscribed in a triangle PQR with PQ = 10 cm, QR = 8 cm and PR = 12 cm. The angle subtended by an arc of a circle at the centre is double the angle .

Step-by-step explanation:

Answer 2

Answer:

60°

Step-by-step explanation:

Tan P=QR/PQ

Tan P=27√3/27

Tan P=√3

Tan P=√3=Tan 60

so p=60°

hope it helps