Question

Consider a right triangle with lengths of the legs are 7and24. The bisector of the right angle divides the hypotenuse into two segments. Find the length of the shorter segment of the hypotenuse to the nearest tenth

Answer 1

Answer:

x = 5.65

Step-by-step explanation:

Consider a right triangle with lengths of the legs are 7and24. The bisector of the right angle divides the hypotenuse into two segments. Find the length of the shorter segment of the hypotenuse to the nearest tenth

Hypotenuse = √7² + 24² = √625  = 25

The bisector of the right angle divides the hypotenuse into two segments.

Let say Shorter Segment = x  then Other Segment = 25 -x

7/24  = x/(25-x)

=> 175 - 7x = 24x

=> 31x = 175

=> x = 175/31

=> x = 5.65