Question

Consider a room filled with air and relative humadity is 75%, calculate the temperature of the windowof the room at which it start condensing

Answer 1

Relative humidity(∅)=75%=0.75

air temperature is 15C

so based on the table at $15^{0} C$

             $P_{sat} =1.7057kpa$

we will get

∅=$0.75=\frac{p_{v} }{p_{s} }$

$P_{v} =0.75*1.7057$

$P_{v} =1.2793kpa$

temperature value is=$10.6^{0} C$

Answer 2

Answer:

the given answer is correct