Question

Consider a sequence
of
seven consecutive integers
The average of the first five integers is 25
i
The average
of all
all the seven integers is​

Answer 1

Answer:

Let the seven consecutive integers be x−3,x−2,x−1,x,x+1,x+2,x+3

Given that average of first five integers is n

Therefore, n=

5

(x−3)+(x−2)+(x−1)+x+(x+1)

⟹5x−5=5n

⟹x−1=n

⟹x=n+1 ------(1)

Average of seven integers is

7

(x−3)+(x−2)+(x−1)+x+(x+1)+(x+2)+(x+3)

=

7

7x

=x=n+1 (from (1))