Math, asked by vevemi2473, 3 months ago

Consider a sequence who's first five terms are: 0, -2, -8, -18, -32. Which function (with domain all integers n≥1) could be used to define and continue this sequence?

Answers

Answered by bhowmik2018piu
1

Step-by-step explanation:

the function is f(n)= -2*n^2

1) f(n)= -2n^2

f(0)=-2*0^2=0

f(1)= -2*1^2= -2

f(2)=-2*2^2= -8

f(3)= -2*3^2= -18

f(4)= -2*4^2= -32

so the first five term of f(n)= -2n^2 is 0,-2,-8,-18,-32

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