Consider a situation in which an object is moving with a uniform velocity along a particular direction. Now a retarding force, F, is applied in the opposite direction. That is, the angle between the two directions is 180 degrees. Let the object stop after a displacement s. In such a situation, the work done by the force, F is taken as negative and denoted by the minus sign. The work done by the force is FX (-S) OR (-F xs).
It is clear from the above discussion that the work done by a force can be either positive or negative.
i. Which force is applied in the opposite direction?
ii. What is the formula of work done?
iii. From the above discussion, what do you know about work done?
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The work done is negative.(-25N)
W= WORK DONE
F = FORCE ACTING ON THE OBJECT
S = DISTANCE/DISPLACEMENT/HEIGHT
W = F * S (For positive work) Equation 1
W = - F * S (For negative work) Equation 2
HERE, we will use Equation 2
Substituting all the values, we get
W =-F * S
W = -5 * 5
W = - 25 N
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