Question

Consider a situation in which the homozygote for an advantageous allele aa experiences a 4% fitness

Answer 1

Answer:

Since p + q =1, then q = 1 - p. The frequency of A alleles is p2 + pq, which equals p2 + p (1 — p) = p2 + p — p2 = p ; that is, p stays the same from one generation to the next. The same can be shown for q.