Question

Consider a situation shown in figure. Spring of
spring constant k = 100 N/m is unstretched
when the system is released from rest.
Assuming no friction in the pulley, find the
maximum elongaton of the spring
(g = 10 m/s)
m = 10 kg​

Answer 1

Answer:

Let mass of the body be m,

Assume that the highest elongation in the spring  be x .

As given No friction in the pulley , Then for the block , Reduction in the potential energy is equal to potential energy stored in spring .

Now, Potential energy in the spring = 1/2 (kx²)

and change in potential energy = mgx 

Hence on equating these two values.

1/2 (kx²) = mgx

.

Hence the maximum elongation in the spring is x = 2mg /k .

Explanation: