Physics, asked by successrex000, 6 months ago

Consider a small ball of radius (r) falling through a viscous liquid of viscosity with a velocity (v) derive the exact form of relation between viscous force (f) experienced by the ball. Given that F=kr^x viscosity^y v^z. Where; k is a dimensionless constant.

Answers

Answered by escelwonderful

11

Answer:

F= k r3 η $\\ \sqrt v$

Explanation:

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