Physics, asked by kassandragvndr5881, 9 months ago

Consider a small cube of volume 1 mm3 at the centre of a circular loop of radius 10 cm carrying a current of 4 A. Find the magnetic energy stored inside the cube.

Answers

Answered by dk6060805
0

Magnetic Energy Stored is 8\pi \times 10^{-14} J

Explanation:

Energy density = B^2/2\mu_0

Total energy stored

= \frac {B^2V}{2\mu_0} = \frac {(\mu_0 i/2r)^2}{2\mu_0} V

= \frac {\mu_0 i^2}{4r^2 \times 2} V

= \frac {4\pi \times10^-^7 \times 4^2 \times 1 \times 10^-^9}{4 \times(10^-^1)^2 \times 2}

= 8\pi \times 10^{-14} J

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