Question

Consider a square loop of

wire loaded with a glass bulb of mass m hanging vertically, suspended in air with its one part in a uniform magnetic field Bwith its direction coming out of the plane of the paper (). Due to the current I flowing

through the loop, there is a magnetic force in upward direction. Calculate the current

I in the loop for which the magnetic force would be exactly balanced by the force on mass m due to gravity.​

Answer 1

.$\bf\large\underline\green{Answer:-}$

Solution: The current I in the loop with

its part in the magnetic field B causes an

upward force Fm in the horizontal part of

the loop, given by

Fm = IBa,

where a is the length of one arm of the

loop.This force is balanced by the force due

to gravity.

∴ Fm = I Ba = mg

For this current, the wire loop will

hang in air.