Question

Consider a square matrix of order 3, prove A(adj; A) (adj; A)A =|A|×I

Answer 1

If there is a square matrix of order n the n

|Adj(A)|=|A|^(n-1)

Proof can be simply like -

[A]×[adj(a)]=|A|×In (here In is identity matrix of order n same as matrix A)

Now just take determinant both sides you will see the above result..

Well now simply n=3 ans is 25

Hope it helps

Pls mark brainliest