Consider a steady-flow carnot cycle with water as the working fluid executed under the saturation dome between the pressure limits of 3 mpa and 10 kpa. water changes from saturated liquid to saturated vapor during the heat addition process. the net work output of this cycle is
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The saturation temperatures fro the two pressures are
10 MPa => 310 C
50 kPa => 81 C
Since it is a steady flow system, the heat required to go from saturated liquid to saturated vapor is
qin = delta enthalphy = 2727 - 1408 = 1319 kJ/kg
where I used steam tables to get the values of the enthalpies. The efficiency of the carnot cycle in this case is
efficiency = 1 - (81+273)/(310+273) = 0.39
and, thus the net work output is
work output = 0.39 * 1319 = 518 kJ / kg
10 MPa => 310 C
50 kPa => 81 C
Since it is a steady flow system, the heat required to go from saturated liquid to saturated vapor is
qin = delta enthalphy = 2727 - 1408 = 1319 kJ/kg
where I used steam tables to get the values of the enthalpies. The efficiency of the carnot cycle in this case is
efficiency = 1 - (81+273)/(310+273) = 0.39
and, thus the net work output is
work output = 0.39 * 1319 = 518 kJ / kg
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