Physics, asked by nikeshilla, 9 months ago

consider a system of blocks X, A, B as shown in the figure . the block A and B have equal mass and are connected by a massless string through a massless pulley the coefficient of friction between block A & X and B x is 0.5. if block X moves on the horizontal frictionless surface what should be its minimum acceleration such that blocks A and B remains stationary

Answers

Answered by DivyanshuRaj21
0

Answer:

You have not sent any figure. pls send it again

Answered by jatinraghav123
0

By balancing forces on block B

Tension in the string (T)=mg=10x10=100N

Friction force on block A = μmg=0.5x10x10=50N

Net force on block A = T - friction force on block A

=100−50=50N

Acceleration of A =

m

Net force on blockA

=

10

50

= 5 m/s

2

The system will move with 5 m/s

2

of acceleration.

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