consider a system of equations x+y+3z=5,x+3y -3z=1,-2x-4y-4z=-10,convert the system of equations in the standard form ax=b
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Answered by
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Answer:
4x-4z=16
Step-by-step explanation:
(x+y+3z)+(x+3y-3z)+(2x-4y-4z) =5+1+10
x+y+3z+x+3y-3z+2x-4y-4z=5+1+10
4x+(-4z) =5+1+10
4x-4x=16
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