Question

Consider a table of mass is 10kg. How much force it experience from another table of mass 20kg seperated by a distance of 100m from each other.​

Answer 1

Explanation:

F=G×

d

2

m×M

m = 50 kg

M = 120 kg

Distance, d = 10 m

G=6.7×10

−11

Nm

2

/kg

2

F=6.67×10

−11

×

10

2

50×120

F=6.67×60×10

−11

F=4.02×10

9

N