Question

Consider a tank made of glass (refractive index 1.5) with a thick bottom. It is filled with a liquid of refractive index μ. A student finds that, irrespective of what the incident angle I (see figure) is for a beam of light entering the liquid, the light reflected from the liquid glass interface is never completely polarized. For this to happen, the minimum value of μ is (A) √(5/3)
(B) 3/√5
(C) 5/√3
(D) 4/3
[JEE Main 2019]

Answer 1

Answer:

D) 4/3

Mate, I tried to solve this. I hope my answer is correct.

One thing is clear, the answer is rational.

Please mark as brainliest

Answer 2

Answer:

3/root 5

Explanation:

Hey DUDE....,

Here is YOUR ANSWER .....,

C < ib here ib is " brewest angle " and C is " critical angle "

Sin C < Sin ib And tan ib = mu ref = 1.5/mu

1/mu < 1.5 / root mu ^ 2 + root 1.5 ^ 2 》》》( 1 )

sin ib = ( 1 )

root ( mu ^ 2 + 1.5 ^ 2 ) < mu × 1.5

mu ^ 2 + 1.5 ^2<( mu × 1.5 ) ^2

mu < 3/ root 5

Hey I tried out my best , Hope it is USEFUL...., Have a GOOD day...,

And please MARK it AS BRILLIANT......