Question

Consider a Telecom Tower BC fixed on top of a building AB. The  distance between base of the building and point P on the ground is 48 m.  From the point P , the angle of elevation of top of the building B is 30°  And the angle of elevation of top of the tower C is 60°  A) What is the height of the building AB? B) What is the angle of depression from the top of the tower to the  point P? C) What is the distance of the top of the building AB from the point P? D) What is the height of the Telecom tower BC ?​

Answer 1

Answer:

Consider the given data.

The height of building AB=60 m.

And angle of the depression of the top and bottom of vertical lamp post CD are observed to be 30

∘

and 60

∘

, respectively shown in the figure.

In the △ADB,

tan60

∘

=

x

60

3

=

x

60

x=

3

60

m

In the △ACP,

tan30

∘

=

x

60−h

3

1

=

3

60

60−h

3

60

=60−h

h=60−20

h=40 m

Therefore,

The distance of between AB and CD is

3

60

m.

The height of lamp post is 40 m.

The difference between the height of the building and the lamp post =60−40=20 m.

solution

Answer 2

Answer:

please refer the above attachment hope it helps