consider a triangle abc with side ab=ac and angle bac = 20 degrees. d is a point on side ac. ad=bc. find angle dbc.
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Firstly,. Triangle ABC measures are=20°+2x=180°. 2x=160,,x=80°
If BD is Bisecting. The angle ABC then Angle DBC=40°
Nice problem, but not sure about the answer
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Let E be a point inside the triangle such that E B = E C = B C. Point P on side BC of triangle ABC such that PC=2BP.
Find ACB if ABC=45º, APC=60º · 0 · given sides and a bisection, find angles in a triangle.
It is also taking place with triangle and denotes both sides as the bisection side.
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