Question

Consider a turbine working under a head of 400 m with an efficiency of 90%. The approximate shaft power developed by the turbine for a flow rate of 20m³/s is

Answer 1

shaft power=efficiency*(water power)

s.p.=efficiency*(density*H*g*Q)

s.p.=0.9*(density*400*9.8*20)

put density of liquid and simply you will find the answer.

Explanation:

Answer 2

A turbine working under a head of 400 m with an efficiency of 90%. The approximate shaft power developed by the turbine for a flow rate of 20 m³/s is 70632 KWatts.

• We know, Efficiency of a turbine (η) = (Shaft Power) / (Water Power)
• Water power is given by = ρ * g * Q * H
• So, water power = 1000 * 9.81 * 20 * 400 = 78480 Kwatt
• Finally, Shaft power = 0.9 * 78480 = 70632 Kwatt.