Consider a uniform electric field E=3×10³i N/C.
(a)what is the flux of the field through the square of 10cm on a side whosr plane is patallel to the yz plane?
(b) what is the flux through the same square if the the normal to its plane makes a 60° angle with the x-axis?
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Answer:
flux=E.dscostheta
= 3×10^3×10^-2cos0
= 3×10^1
now flux at angle 60
3×10^3×10×10^-2cos60
3/2×10^-1
1.5×10^-1
or0.15
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