Question

Consider a uniform electric field E = 3 x 10^3 i^ (i cap) N/C (Newton per Coulomb). Calculate the flux of this field through a square of surface area 10cm² when
i) its plane is parallel to the Y-Z plane, and
ii) the normal to its plane makes a 60° angle with the X-axis.

Answer 1

Answer:

Part i)

the flux of this field through a square when  its plane is parallel to the Y-Z plane is 3 N-m^2/C, and

Part ii)

the flux of this field through a square when  the normal to its plane makes a 60° angle with the X-axis is 1.5 Nm^2/C.

Explanation:

Part i)

As we know that the electric flux due to electric field is given as

$\phi = E. A$

$\phi = EA cos\theta$

here we know that plane is YZ plane and angle of its Normal with electric field is ZERO degree

so we will have

$\phi = EA cos0$

$\phi = (3 \times 10^3)(10 \times 10^{-4})cos0$

$\phi = 3 N-m^2/C$

Part ii)

As we know that the electric flux due to electric field is given as

$\phi = E. A$

$\phi = EA cos\theta$

here we know angle of its Normal with electric field is 60 degree

so we will have

$\phi = EA cos60$

$\phi = (3 \times 10^3)(10 \times 10^{-4})cos60$

$\phi = 1.5 N-m^2/C$

#Learn

Topic : Electric Flux

https://brainly.in/question/10801562