Question

Consider △ABC. L is the mid point of BC. Squares AFGB and ACDE are drawn exterior to △ABC. Let M be mid point of diagonal of ✷AFGB and N be mid point of diagonal of ✷ACDE respectively. Prove that LM ⊥ LN and LM = LN.

Answer 1

Answer:

ANSWER

Using mid point theorem, A line segment joining the mid points of the two sides of the triangle, is equal to half the length of the third side.

D and E are the mid points. Hence,

DE=

2

1

AC

DE=

2

1

(6.4)

DE=3.2cm

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