Consider an A. P whose nth term is 2n+1.
find the sum of first ten terms.
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Given nth term of an AP is 2n + 1.
Substitute n = 1, we get
= > 2(1) + 1
= > 3.
we know that sum of n terms = n/2(a + l)
= n/2(3 + 2n + 1)
= n/2(2n + 4).
Sum of first tern terms = 10/2(2(10) + 4)
= 5(20 + 4)
= 5(24)
= 120.
Therefore, the sum of first tern terms = 120.
Hope this helps!
siddhartharao77:
:-)
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