Math, asked by vandanaas2005, 8 months ago

consider an arithmetic sequence 71,68,65 a,how many positive numbers are in this sequence b, which is the largest negative number in this sequence

Answers

Answered by rohitrs0908
19

Answer:

Step-by-step explanation:

71,68,65 ...........

Common difference = -3

nth terms = 71 + (n-1)(-3)= 71 - 3n +3 = 74 - 3n

a) 74 - 3n > 0

74 > 3n

n < 74/3

n < 24.6

So there are 24 positive terms

b) Largest negative term will be 25th term

=74-3(25) = 74-75= -1

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