consider an arithmetic sequence 71,68,65 a,how many positive numbers are in this sequence b, which is the largest negative number in this sequence
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Answer:
Step-by-step explanation:
71,68,65 ...........
Common difference = -3
nth terms = 71 + (n-1)(-3)= 71 - 3n +3 = 74 - 3n
a) 74 - 3n > 0
74 > 3n
n < 74/3
n < 24.6
So there are 24 positive terms
b) Largest negative term will be 25th term
=74-3(25) = 74-75= -1
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